fix our ostream << hex << char
Even when hex modifier is used, 'char' should be printed as characters, this is particularly relevant with 0. e.g. out << (char)0, should write a nul terminator, not "0".
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committed by
Mathias Agopian
parent
da0d94caf2
commit
1716f9e7cd
@@ -73,8 +73,8 @@ const char* ostream::getFormat(ostream::type t) const noexcept {
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switch (t) {
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case type::SHORT: return mShowHex ? "0x%hx" : "%hd";
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case type::USHORT: return mShowHex ? "0x%hx" : "%hu";
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case type::CHAR: return mShowHex ? "0x%x" : "%c";
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case type::UCHAR: return mShowHex ? "0x%x" : "%c";
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case type::CHAR: return "%c";
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case type::UCHAR: return "%c";
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case type::INT: return mShowHex ? "0x%x" : "%d";
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case type::UINT: return mShowHex ? "0x%x" : "%u";
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case type::LONG: return mShowHex ? "0x%lx" : "%ld";
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