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Functions with vararg tables don't need hidden args.

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Vararg functions with vararg tables don't use the arguments hidden in
the stack; therfore, it doesn't need to build/keep them.
This commit is contained in:
Roberto I
2025-11-28 15:12:51 -03:00
parent f33cc4ddec
commit a07f6a8241
9 changed files with 71 additions and 44 deletions
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6
lparser.c
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@@ -304,7 +304,7 @@ static void check_readonly (LexState *ls, expdesc *e) {
break;
}
case VVARGIND: {
fs->f->flag |= PF_VATAB; /* function will need a vararg table */
needvatab(fs->f); /* function will need a vararg table */
e->k = VINDEXED;
} /* FALLTHROUGH */
case VINDEXUP: case VINDEXSTR: case VINDEXED: { /* global variable */
@@ -1057,7 +1057,7 @@ static void constructor (LexState *ls, expdesc *t) {
static void setvararg (FuncState *fs) {
fs->f->flag |= PF_ISVARARG;
fs->f->flag |= PF_VAHID; /* by default, use hidden vararg arguments */
luaK_codeABC(fs, OP_VARARGPREP, 0, 0, 0);
}
@@ -1283,7 +1283,7 @@ static void simpleexp (LexState *ls, expdesc *v) {
}
case TK_DOTS: { /* vararg */
FuncState *fs = ls->fs;
check_condition(ls, fs->f->flag & PF_ISVARARG,
check_condition(ls, isvararg(fs->f),
"cannot use '...' outside a vararg function");
init_exp(v, VVARARG, luaK_codeABC(fs, OP_VARARG, 0, fs->f->numparams, 1));
break;